(3/5)^2x-1=25/9

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Solution for (3/5)^2x-1=25/9 equation: 



(3/5)^2x-1=25/9

We move all terms to the left:

(3/5)^2x-1-(25/9)=0



Domain of the equation: 5)^2x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+3/5)^2x-1-(+25/9)=0

We get rid of parentheses

(+3/5)^2x-1-25/9=0

We calculate fractions


()/5^2x*9)+(-125x)/5^2x*9)-1=0

We calculate fractions

We do not support expression: x^6

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